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920-167 Exam

NCSS-Contact Center RIS.6.0 Application Developer

  • Exam Number/Code : 920-167
  • Exam Name : NCSS-Contact Center RIS.6.0 Application Developer
  • Questions and Answers : 60 Q&As
  • Update Time: 2009-12-30
  • Price: $ 102.00 $ 60.00

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Exam : Nortel 920-167
Title : NCSS-Contact Center RIS.6.0 Application Developer


1. A customer with a Contact Center Manager Server Rls. 6.0 is currently in the process of writing scripts using Contact Center Manager Administration Rls. 6.0. If the customer needs to check the syntax of some scripting commands in the Script Command Reference Panel, where can the syntax be found?
A. in the Script Editor
B. in the Script Wizard
C. in the Script Variable window
D. in the Script Reference window
Answer: A

2. Your customer uses Contact Center Manager Server Rls. 6.0 and wants to understand the effect on a call when a blind transfer occurs. The call variables change. What is the change?
A. The call variables are lost.
B. The call variables become invalid.
C. Two sets of call variable are generated.
D. The call variables of the original call are combined with the consultative call.
Answer: D

3. A customer has Contact Center Manager Server Rls. 6.0. Which commands are used to access the value of a wild variable?
A. Get Info
B. Assign To
C. Send Request
D. Readvar/Savevar
Answer: D

4. A customer has a Communication Server (CS) 1000M Rls. 0 system that is running Contact Center Manager Server (CCMS) Rls. 6.0 and CallPilot Rls. 0. As part of CCMS-CallPilot integration, CallPilot agents (voice channels) must be configured on the CS 1000M. What is the correct configuration for CallPilot voice channels?
A. Key 0 of each channel must be configured as an AST set, while IAPG must be set to 0.
B. Keys 0 and 1 of each channel must be configured as an AST set, while IAPG must be set to 0.
C. Key 1 of each channel must be configured as an AST set, while IAPG must be set to 1 for each channel.
D. Keys 0 and 1 of each channel must be configured as an AST set, while IAPG must be set to 1 for each channel.
Answer: B